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Select function

Hi, I have created a Select function to filter a range of data, and it's working fine, but I need to divide this data by 10. I think it's simple, but I'm new on Klipfolio and having problems.

 

This is my formula:

 

This is my attempt:

 

Thanks.

4 comments

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    Keely Davison

    Hi Jeferson,

    If the select is returning the data you want then I think you want to count the result and then divide by 10.  I am assuming the data returned is a list of values "Cadastor Completo".  Since these values are not numeric, dividing by 10 does not make sense with out some other manipulation like a count. 

    If the count is what you want, you can change the SELECT to a COUNTIF and then divide by 10 as follows:

    COUNTIF(AND(@deals list,C:C = "Cadastor Completo",@deals list,F:F<2013))/10

    Let us know if you need more help with this or if I have misunderstood what you are looking for. 

    Keely

  • 0
    Avatar
    Jeferson Sousa

    Hi Keely, thank you. It's working fine.

    But if I need two or more filters, like: "Cadastro completo" or "Cadastro incompleto" or "Lead"... How can I do it?

  • 0
    Avatar
    Keely Davison

    Hi Jeferson,

    For the case you describe I think IN is your best option

    e.g. IN(@deals list,C:C, ARRAY("Cadastro completo","Cadastro incompleto","Lead"))

    This replaces the part of your formula that was doing @deals list,C:C = "Cadastor Completo"

    And the result will count any value in C:C that is one of the 3 values.

    If instead you want a count for completo, incompleto and lead separately, e.g. in a chart or table, you can do something like

    Column 1: deals list,C:C

    Column 2: repeat(1,countall(deals list,C:C))/10

    On column 1 go to properties and select add filter, in the filter pick the values you want to include in the table

    On column 1 in properties check "group repeating labels"

    Here is a document on using group, sort and filter actions for more details:

    https://support.klipfolio.com/hc/en-us/articles/222017088-Using-the-Filter-Group-Aggregate-and-Sort-actions-videos-

    Keely

     

     

     

  • 0
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    Jeferson Sousa

    Hi Keely, thanks. It's working fine.

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